Question

I have:

active = Node.objects.filter(status = 'a')
potential = Node.objects.filter(status = 'p')
hotspot = Node.objects.filter(status = 'h')

I’m wondering: is it’s possible to do it in a better way?

EDIT: maybe i didn’t explain myself very well. I need to have 3 lists with the 3 different status. If I do just 1 query then I will have to loop over the list to make 3 new lists, but if the list if very long wouldn’t that be inefficient?

Answer 1

Even better, use in:

Node.objects.filter(status__in=['a', 'p', 'h'])

Edit after comment Don’t know why that would be inefficient. Perhaps one improvement would be to add .order_by('status') so you get an ordered queryset, then split when you iterate through. Likely to be a micro-optimization though.