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Home/ Questions/Q 6684035
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Editorial Team
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Editorial Team
Asked: May 26, 20262026-05-26T04:53:31+00:00 2026-05-26T04:53:31+00:00

I have an array declared in my header file like this: int snapshot[kSnapshotSize]; which

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I have an array declared in my header file like this:

int snapshot[kSnapshotSize];

which I would really love to init like this in my implementation file:

snapshot[kSnapshotSize] = {[0 ... kSnapshotSize-1] = 5};

however the compiler complains: “Expected expression”

Can anyone tell me what I’m doing wrong?

UPDATE: int snapshot[kSnapshotSize] = {[0 ... kSnapshotSize] = 5}; seems to work, so probably I’m missing something basic. I think I can use memset, but would first want to be sure this is not possible (and why)

UPDATE 2: As many of you pointed out, it seems that it’s only possible to init an array like that not to populate it later. I end up using a for loop.

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  1. Editorial Team
    Editorial Team
    2026-05-26T04:53:32+00:00Added an answer on May 26, 2026 at 4:53 am

    I presume you mean

    int snapshot[kSnapshotSize] = {[0 ... kSnapshotSize - 1] = 5};
    

    But that use of ... is a gcc-specific extension. If you don’t mind being limited to gcc, that’s ok.

    memset() won’t work; it sets each byte of the target to the specified value.

    For portability, your best bet is to use an explicit loop to set each element.

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