If I have an array declared like this:
int a[3][2];
stored at address A.
Then a+1 is equal to A+2*4, this is clear to me,
but why is &a+1 equal to A+6*4?
If I have an array declared like this: int a[3][2]; stored at address A
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If I have an array declared like this:
int a[3][2];
stored at address A.
Then a+1 is equal to A+2*4, this is clear to me,
but why is &a+1 equal to A+6*4?
ais an array ofint[2]. Which has size2 * sizeof(int). That’s whya + 1 = A + 2*4. (sincesizeof(int) = 4in your case)However,
&ais a pointer toint[3][2]. Sincesizeof(int[3][2]) = 6 * sizeof(int), therefore:&a + 1 = A + 6*4