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Home/ Questions/Q 7823733
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Editorial Team
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Editorial Team
Asked: June 2, 20262026-06-02T08:21:31+00:00 2026-06-02T08:21:31+00:00

I have an array ( double ) : ox_test with a known number of

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I have an array ( double ) : ox_test with a known number of elements.

when I code :

Array.Sort(ox_test);

and then, just to see if the array it’s sorted :

for (int y = 1; y <= ox_test.Length; y++)
     MessageBox.Show(".x: " + ox_test[y]);

.. I get … 0, 0, 0, 0, 0 ( if the number of elements was 5 ). Please help, thank you!

So i modified the both for loops:

for (int y = 0; y < ox_test.Length; y++)
    MessageBox.Show(".x: " + ox_test[y]);
    // HERE  i get the values not sorted but != 0

Array.Sort(ox_test);

for (int y = 0; y < ox_test.Length; y++)
    MessageBox.Show(".x s: " + ox_test[y]);
    // HERE i get only 0 values
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  1. Editorial Team
    Editorial Team
    2026-06-02T08:21:32+00:00Added an answer on June 2, 2026 at 8:21 am
    // sort double array
    double[] doubleArray = new double[5] { 8.1, 10.2, 2.5, 6.7, 3.3 };
    Array.Sort(doubleArray);
    // write array
    foreach (double d in doubleArray) Console.Write(d + " ");  // output: 2.5 3.3 6.7 8.1 10.2
    
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