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Home/ Questions/Q 662671
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Editorial Team
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Editorial Team
Asked: May 13, 20262026-05-13T23:24:15+00:00 2026-05-13T23:24:15+00:00

I have an double array alist[1][1]=-1 alist2=[] for x in xrange(10): alist2.append(alist[x]) alist2[1][1]=15 print

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I have an double array

alist[1][1]=-1
alist2=[]
for x in xrange(10):
    alist2.append(alist[x])
alist2[1][1]=15

print alist[1][1]

and I get 15. Clearly I’m passing a pointer rather than an actual variable… Is there an easy way to make a seperate double array (no shared pointers) without having to do a double for loop?

Thanks,
Dan

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  1. Editorial Team
    Editorial Team
    2026-05-13T23:24:15+00:00Added an answer on May 13, 2026 at 11:24 pm

    A list of lists is not usually a great solution for making a 2d array. You probably want to use numpy, which provides a very useful, efficient n-dimensional array type. numpy arrays can be copied.

    Other solutions that are usually better than a plain list of lists include a dict with tuples as keys (d[1, 1] would be the 1, 1 component) or defining your own 2d array class. Of course, dicts can be copied and you could abstract copying away for your class.

    To copy a list of lists, you can use copy.deepcopy, which will go one level deep when copying.

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