I have an array of typedef structure.
It is declared as such:
vertex vertexArray[numberVertices];
I then have this in my main code:
for(i=0;i<numberVertices;i++)
{
if(vertexArray[i].source == 5)
{
source = vertexArray[i].number;
walk(vertexArray, vertexArray[i], source, headMaxPairList );
}
}
To hopefully perform the walk:
void walk(vertex *vertexArray, vertex v, int source, maxPairing *head)
{
int i;
adjEdge *traverse;
int moveVertex;
int sink;
moveVertex = vertexArray[v.number-1].number;
if(vertexArray[moveVertex-1].color != 5 && vertexArray[moveVertex-1].sink == 5)
{
sink = vertexArray[moveVertex-1].number;
vertexArray[moveVertex-1].color = 5;
addMaxPair(head, source, sink);
}
else
{
walk(vertexArray, vertexArray[moveVertex-1], source, head);
}
}
However, I am getting a seg-fault on the function:
in walk (vertexArray=Cannot access memory at address 0x7fffff3fefe8
I believe this has to do with the way I’m passing vertexArray.
It is my understanding that arrays are actually pointers, hence the vertex *vertexArray and then an individual member is just a vertex, not a pointer hence vertex v.
If anyone could help me with getting this passed correctly I’d be appreciative.
Side note, if anyone can tell if my walk looks like it’ll work correctly that’s a plus!
Arrays are not same as pointers.
Read the following Links for clarification:
Q: So what is meant by the “equivalence of pointers and arrays” in C?
http://c-faq.com/aryptr/aryptrequiv.html
Q: But I heard that char a[] was identical to char *a.
http://c-faq.com/aryptr/aryptr2.html
To avoid Seg-Fault, add the following checks to walk() function: