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Asked: 2026-06-11T14:33:56+00:00

I have an std::deque<CustomType> , I am trying to remove a member whose location

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I have an std::deque<CustomType>, I am trying to remove a member whose location I do not know. Therefore, I am first finding it and then removing it. 

/* 
  Remove from - members, which is the private variable of std::deque<User> type
*/
void Group::remove_member(User u) {  
    if(this->is_member(u)) {
           std::deque<User>::iterator iter;
           iter = std::find(this->members.begin(), this->members.end(), u);
           if(iter != this->members.end()) {
                this->members.erase(iter);
           }
     }
}

However, the compiler (GCC) is throwing an error which seems like missing Operator Overloading.

In file included from /usr/lib/gcc/x86_64-redhat-linux/4.4.6/../../../../include/c++/4.4.6/algorithm:62,
from Group.cpp:4:
/usr/lib/gcc/x86_64-redhat-linux/4.4.6/../../../../include/c++/4.4.6/bits/stl_algo.h: In function ‘_RandomAccessIterator std::__find(_RandomAccessIterator, _RandomAccessIterator, const _Tp&, std::random_access_iterator_tag) [with _RandomAccessIterator = std::_Deque_iterator<User, User&, User*>, _Tp = User]’:
/usr/lib/gcc/x86_64-redhat-linux/4.4.6/../../../../include/c++/4.4.6/bits/stl_algo.h:4224:   instantiated from ‘_IIter std::find(_IIter, _IIter, const _Tp&) [with _IIter = std::_Deque_iterator<User, User&, User*>, _Tp = User]’
Group.cpp:36:   instantiated from here
/usr/lib/gcc/x86_64-redhat-linux/4.4.6/../../../../include/c++/4.4.6/bits/stl_algo.h:174: error: no match for ‘operator==’ in ‘__first.std::_Deque_iterator<_Tp, _Ref, _Ptr>::operator* [with _Tp = User, _Ref = User&, _Ptr = User*]() == __val’
/usr/lib/gcc/x86_64-redhat-linux/4.4.6/../../../../include/c++/4.4.6/bits/stl_algo.h:178: error: no match for ‘operator==’ in ‘__first.std::_Deque_iterator<_Tp, _Ref, _Ptr>::operator* [with _Tp = User, _Ref = User&, _Ptr = User*]() == __val’
/usr/lib/gcc/x86_64-redhat-linux/4.4.6/../../../../include/c++/4.4.6/bits/stl_algo.h:182: error: no match for ‘operator==’ in ‘__first.std::_Deque_iterator<_Tp, _Ref, _Ptr>::operator* [with _Tp = User, _Ref = User&, _Ptr = User*]() == __val’
/usr/lib/gcc/x86_64-redhat-linux/4.4.6/../../../../include/c++/4.4.6/bits/stl_algo.h:186: error: no match for ‘operator==’ in ‘__first.std::_Deque_iterator<_Tp, _Ref, _Ptr>::operator* [with _Tp = User, _Ref = User&, _Ptr = User*]() == __val’
/usr/lib/gcc/x86_64-redhat-linux/4.4.6/../../../../include/c++/4.4.6/bits/stl_algo.h:194: error: no match for ‘operator==’ in ‘__first.std::_Deque_iterator<_Tp, _Ref, _Ptr>::operator* [with _Tp = User, _Ref = User&, _Ptr = User*]() == __val’
/usr/lib/gcc/x86_64-redhat-linux/4.4.6/../../../../include/c++/4.4.6/bits/stl_algo.h:198: error: no match for ‘operator==’ in ‘__first.std::_Deque_iterator<_Tp, _Ref, _Ptr>::operator* [with _Tp = User, _Ref = User&, _Ptr = User*]() == __val’
/usr/lib/gcc/x86_64-redhat-linux/4.4.6/../../../../include/c++/4.4.6/bits/stl_algo.h:202: error: no match for ‘operator==’ in ‘__first.std::_Deque_iterator<_Tp, _Ref, _Ptr>::operator* [with _Tp = User, _Ref = User&, _Ptr = User*]() == __val’
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1 Answer

  1. Editorial Team

    See my comment.

    I have a feeling you have not declared bool User::operator==(const User&)

    The error is telling you that its attempting to do *iterator == ... inside the implementation of std::find. The problem, however, is that you have not overloaded operator== for User. Try declaring a member function inside User as follows…

    bool operator==(const User&);

    Now, define it to provide some meaningful semantic equality between Users, otherwise std::find doesn’t know how to compare them.

    As a side note, why doesn’t Group::remove_member take const User& rather than User?

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