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Home/ Questions/Q 3491046
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Editorial Team
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Editorial Team
Asked: May 18, 20262026-05-18T11:35:23+00:00 2026-05-18T11:35:23+00:00

I have been coding in Java(Mainly) and .Net for a while. What I found

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I have been coding in Java(Mainly) and .Net for a while.

What I found is that the || logical operator in .Net is different in result to the || operator in Java.

Lets look at the following Java code:

Object obj = null;

if(obj == null || obj.toString().isEmpty()){
    System.out.println("Object is null");
}

The result of the code above will be:

Object is null

The reason for that is because obj == null is true and the second expression wasn’t evaluated. If it was, I would have received a java.lang.NullPointerException.

And if I used the single or (|) I would also received a NullPointerException (Both are evaluated).

My question is the following:

If the code was C#, I will always get a ObjectReferenceNotSet etc. exception because the obj value is null and the second expression is always evaluated (Regardless of the operator), meaning the result is different in C# than in Java.
If I would to change the C# code to work properly, I have to create two if statements.

Is there not an easier way to do this in C# to be similar to Java? (Keep it in one if with 2 expressions)

Thank you.

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  1. Editorial Team
    Editorial Team
    2026-05-18T11:35:24+00:00Added an answer on May 18, 2026 at 11:35 am

    The || operator in C# is short-circuiting, just like in Java. As is &&. The | and & operators are not short-circuiting, just like in Java.

    If your results are different, there is a bug in the code. Can you show us the offending C# please?

    This works fine:

        object obj = null;
    
        if(obj == null || string.IsNullOrEmpty(obj.ToString())) {
            Console.WriteLine("Object is null");
        }
    
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