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Home/ Questions/Q 6124603
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Editorial Team
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Editorial Team
Asked: May 23, 20262026-05-23T16:09:06+00:00 2026-05-23T16:09:06+00:00

I have below code written with Eclipse ide: public interface X { final public

  • 0

I have below code written with Eclipse ide:

public interface X
{
  final public static int SOME_CONST = 0;
}
public class Handle implements X
{
  protected void methodHandle () { }
 //...
}

public class User implements X
{
  Handle handle = new Handle();
  private void methodUser ()
  {
    Y y = new Y()  // anonymous inner class
    {
      public void methodY ()
      {
        handle.methodHandle (); // <--- why this is NOT giving error ?
      }
    }
  }
}

Even though Handle.methodHandle () is protected, it’s still callable from the inner method of an anonymous inner class method ? Why is it happening, am I missing something ? The only relation between Handle and User is that they are implementing same X.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-23T16:09:07+00:00Added an answer on May 23, 2026 at 4:09 pm

    If both classes are in the same package, the protected method can be called.

    See this for more details.

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