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Home/ Questions/Q 3635110
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Editorial Team
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Editorial Team
Asked: May 19, 20262026-05-19T00:51:47+00:00 2026-05-19T00:51:47+00:00

I have written the below code for LCS. It works for many cases but

  • 0

I have written the below code for LCS. It works for many cases but breaks for the one below. I do not understand where my code is breaking. Please help. The code is in C#

namespace LongestCommonSubsequenceBF
{
class Program
{
    static void Main(string[] args)
    {

        string B = "AAACCGTGAGTTATTCGTTCTAGAA";
        string A = "CACCCCTAAGGTACCTTTGGTTC";
        //find LCS in A,B starting from index 0 of each
        int longestCommonSubsequence = LCS(A, B, 0, 0);
        Console.WriteLine(longestCommonSubsequence);
        Console.Read();

    }

    //Find the longest common subsequnce starting from index1 in A and index2 in B
    //Pass A as shorter string
    public static int LCS(String A, String B, int index1, int index2)
    {
        int max = 0;
        if (index1 == A.Length)
        {
            //You have reached beyond A and thus no subsequence
            return 0;
        }
        if (index2 == B.Length)
        {   //you may reach end of 2nd string. LCS from that end is 0
            return 0;
        }

        for (int i = index1; i < A.Length ; i++)
        {
            int exist = B.IndexOf(A[i],index2);
            if (exist != -1)
            {
             //   found = true;

                int temp = 1 + LCS(A, B, i + 1, exist + 1);
                if (max < temp)
                {
                    max = temp;
                }


            }


        }
        return max;

    }
  }
}
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  1. Editorial Team
    Editorial Team
    2026-05-19T00:51:47+00:00Added an answer on May 19, 2026 at 12:51 am

    Why do you think your algorithm is broken? The longest common subsequence is ACCTAGTATTGTTC, which is 14 characters long:

    string B = "AAACCGTGAGTTATTCGTTCTAGAA";
                  ^^^ ^ ^^ ^^^^ ^^^^
    
    string A = "CACCCCTAAGGTACCTTTGGTTC";
                 ^^^  ^ ^^ ^^  ^^ ^ ^^^
    

    (I modified your algorithm to return the sequence instead of just the length.)

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