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Home/ Questions/Q 9140203
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Editorial Team
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Editorial Team
Asked: June 17, 20262026-06-17T09:29:08+00:00 2026-06-17T09:29:08+00:00

I have code as following vector<unique_ptr<int>> v; v.insert(v.end(), new int(1)); // this is okay

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I have code as following

vector<unique_ptr<int>> v;
v.insert(v.end(), new int(1)); // this is okay
v.push_back(new int(1)); // this is wrong, cannot convert int* to unique_ptr<int>&&

Why does the compilation (vc2010) show the differences? Thanks.

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  1. Editorial Team
    Editorial Team
    2026-06-17T09:29:09+00:00Added an answer on June 17, 2026 at 9:29 am

    That’s because in VS2010, v.insert(v.end(), new int(1)); is optimized to callstd::vector::emplace_back which construct object in place while std::vector::push_back will try to copy/convert int* to std::unique_ptr<int> then it failed. To make push smart pointers into STL container you can specify exact type:

    v.insert(v.end(), unique_ptr<int>(new int(1))); 
    v.push_back(unique_ptr<int>(new int(1))); 
    

    Or simply call

    v.emplace_back(new int(1));
    

    I’ve tested your code on VS2010 and VS2012, howerver VS2012 disallows v.insert(v.end(), new int(1));, but emplace_back works in both cases.

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