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Home/ Questions/Q 8725951
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Editorial Team
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Editorial Team
Asked: June 13, 20262026-06-13T08:09:22+00:00 2026-06-13T08:09:22+00:00

I have the following code #include <vector> #include <iostream> class A{ private: std::vector<int> x;

  • 0

I have the following code

#include <vector>
#include <iostream>

class A{
    private:
    std::vector<int> x;
    A(){
        // here is a code to open and initialize several devices
        // it is allowed to be called once only!!!
        std::cout << "constructor called" << std::endl;
    };

    virtual ~A(){
        // here is a code to close several devices
        // it is allowed to be called once only!!!
        std::cout << "destructor called" << std::endl;
    };


    public:
    static A & getA(){
        static A* singleton = new A;
        std::cout << "singleton got" << std::endl;
        return *singleton;
    };

};


int main(int argc, char** argv){

    A a = A::getA();

    return(0);
}

According to many recommendations the destructor is private to be called once only at end of program.
But i have the compiler error:

Test.cpp: In function 'int main(int, char**)':
Test.cpp:12:10: error: 'virtual A::~A()' is private
Test.cpp:29:19: error: within this context
Test.cpp:12:10: error: 'virtual A::~A()' is private
Test.cpp:29:19: error: within this context

Of cause, I can make constructor and/or destructor public and have no any errors like that. But I need to be sure that both of them are called once and only once.
How?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-13T08:09:23+00:00Added an answer on June 13, 2026 at 8:09 am

    Better use this method of singleton constructor:

    static A* getA(){
        static A singleton;
        std::cout << "singleton got" << std::endl;
        return &singleton;
    };
    

    Link for more info is Here

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