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Home/ Questions/Q 6185907
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Editorial Team
  • 0
Editorial Team
Asked: May 24, 20262026-05-24T01:47:48+00:00 2026-05-24T01:47:48+00:00

I have code that should: Generate ten <input> s – done Hide all except

  • 0

I have code that should:

  1. Generate ten <input>s – done
  2. Hide all except first three – done
  3. Show the next input when something is changed in the last visible one.
    This part doesn’t work!

How can I fix it?

for (var i = 0; i < 10; ++i) {

    if (i == 0) {

        $('#tags').append('<input name="group_interests[]" class="group_interests" type="text" />');

    } else {

        $('#tags').append('<input name="group_interests[]" class="group_interests default_text" type="text" value="start typing to see the list" />');

    }

}

$('#tags .group_interests:gt(2)').hide();

$('#tags .group_interests:visible').last().focus( function() {

    $(this).next().show();

});
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-24T01:47:50+00:00Added an answer on May 24, 2026 at 1:47 am

    Your focus is always bound to the same input.
    Try this instead:

    for (var i = 0; i < 10; ++i) {
        if (i == 0) {
            $('#tags').append('<input name="group_interests[]" class="group_interests" type="text" />');
        } else {
            $('#tags').append('<input name="group_interests[]" class="group_interests default_text" type="text" value="start typing to see the list" />');
        }
    }
    
    $('#tags .group_interests:gt(2)').hide();
    
    $('#tags .group_interests:visible').last().focus(showNext);
    
    function showNext() {
        $(this).unbind('focus').next().show().focus(showNext);
    }
    
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