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Home/ Questions/Q 5992059
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Editorial Team
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Editorial Team
Asked: May 22, 20262026-05-22T23:28:37+00:00 2026-05-22T23:28:37+00:00

I have created a sparse matrix using MEX and also created a sparse matrix

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I have created a sparse matrix using MEX and also created a sparse matrix using MATLAB. To fill in the values of the matrix i have used same formula.
Now to check if the both the matrices are equal I used result=(A==B). result returns 1 for all indices, which implies that all the matrix elements are equal.
But if I do find(A-B) it returns some indices, which indicates that at these indices the values are non-zero. How is this possible?

Note: When i compare the value at these indices it shows equal !

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  1. Editorial Team
    Editorial Team
    2026-05-22T23:28:38+00:00Added an answer on May 22, 2026 at 11:28 pm

    I’m guessing you have values of infinity cropping up in your matrices at the same points. For example:

    >> A = Inf;
    >> B = Inf;
    >> A == B
    
    ans =
    
         1  %# They are treated as equal...
    
    >> A-B
    
    ans =
    
       NaN  %# ...but their difference actually results in NaN...
    
    >> find(A-B)
    
    ans =
    
         1  %# ...which is treated as a non-zero value.
    

    The discrepancy here results from the fact that certain operations involving infinity result in NaN values. You can check to see if you have any infinities in A and B by using the function ISINF like so:

    any(isinf(A(:)))
    any(isinf(B(:)))
    

    And if you get a value of 1 (i.e. true), then the presence of infinities is likely the source of your discrepancy.

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