Question

I have developed an application which contains servlet and few java classes and additionally an html page named home.html which is the opening page..

My web.xml is in this format..

<servlet>
    <servlet-name>hello</servlet-name>
    <servlet-class>com.saral.MyServlet</servlet-class>
  </servlet>   
     <servlet-mapping>
    <servlet-name>hello</servlet-name>
     <url-pattern>/helloServlet</url-pattern>
  </servlet-mapping> 

   <welcome-file-list>
    <welcome-file>FirstDemo/WebContent/home.html</welcome-file>
  </welcome-file-list>

  <listener>
  <listener-class>com.saral.SessionCounter</listener-class>
</listener>

Now my query is that after deployment on tomcat the main page get opened is ..
http://imageshack.us/photo/my-images/835/ie1.png/

but I want this page to be get loaded as first one
http://imageshack.us/photo/my-images/651/ie3f.jpg/

Please advise me what changes need to be done , so that my opening page becomes correct

Answer 1

If your home.html to appear as your home page then just make changes to welcome-file-list tag in your web.xml

<welcome-file-list>
    <welcome-file>home.html</welcome-file>
</welcome-file-list>