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Asked: 2026-05-27T19:15:08+00:00

I have done my research but have found nothing specific enough to my problem

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I have done my research but have found nothing specific enough to my problem
I have an HTML form, asking for data, then a php script that is suppose to put the data in a mysql database

When i try it on my localhost, i dont get any errors
but when i check on phpmyadmin, there is no new data

the html:

<html>
<head>

<form action="insert.php" method="post">
ID: <input type="text" name="ID"><br>
Family ID: <input type="text" name="Family_ID"><br>
First Name: <input type="text" name="First_Name"><br>
Last Name: <input type="text" name="Last_Name"><br>
Gender: <input type="text" name="Gender"><br>
Birthday: <input type="text" name="Birthday"><br>
Birthplace: <input type="text" name="Birthplace"><br>
Father ID: <input type="text" name="Father_ID"><br>
Mother ID: <input type="text" name="Mother_ID"><br>
Maiden Name: <input type="text" name="Maiden_Name"><br>
Mariage ID: <input type="text" name="Mariage_ID"><br>
Deathdate: <input type="text" name="Deathdate"><br>
Deathplace: <input type="text" name="Deathplace"><br>
Grave Location: <input type="text" name="Grave_Location"><br>
Email: <input type="text" name="Email"><br>
Phone: <input type="text" name="Phone"><br>
Address: <input type="text" name="Adress"><br>
Bio: <input type="text" name="Bio"><br>
Studies: <input type="text" name="Travail"><br>
Travail: <input type="text" name="Travail"><br>
Photo: <input type="text" name="Photo"><br>
Fete: <input type="text" name="Fete"><br>
<input type="Submit">

</form>
</head>
<body>
</body>
</html>

the php:

$username='root';
$password='121395';
$database='genealogy';
mysql_connect("localhost",$username,$password);
@mysql_select_db($database) or die( 'Unable to select database');
echo "Connected to MySQL";

$ID=mysql_real_escape_string($_POST['ID']);
$Family_ID=mysql_real_escape_string($_POST['Family_ID']);
$First_Name=mysql_real_escape_string($_POST['First_Name']);
$Last_Name=mysql_real_escape_string($_POST['Last_Name']);
$Gender=mysql_real_escape_string($_POST['Gender']);
$Birthday=mysql_real_escape_string($_POST['Birthday']);
$Birthplace=mysql_real_escape_string($_POST['Birthplace']);
$Father_ID=mysql_real_escape_string($_POST['Father_ID']);
$Mother_ID=mysql_real_escape_string($_POST['Mother_ID']);
$Maiden_Name=mysql_real_escape_string($_POST['Maiden_Name']);
$Mariage_ID=mysql_real_escape_string($_POST['Mariage_ID']);
$Deathdate=mysql_real_escape_string($_POST['Deathdate']);
$Deathplace=mysql_real_escape_string($_POST['Deathplace']);
$Grave_Location=mysql_real_escape_string($_POST['Grave_Location']);
$Email=mysql_real_escape_string($_POST['Email']);
$Phone=mysql_real_escape_string($_POST['Phone']);
$Address=mysql_real_escape_string($_POST['Adress']);
$Bio=mysql_real_escape_string($_POST['Bio']);
$Travail=mysql_real_escape_string($_POST['Travail']);
$Photo=mysql_real_escape_string($_POST['Photo']);
$Fete=mysql_real_escape_string($_POST['Fete']);


$query = "INSERT INTO bouan (ID, Family_ID, First_Name, Last_Name, Gender, Birthday, 
Birthplace, Father_ID, Mother_ID, Maiden_Name, Mariage_ID,Deathdate, Deatchplace,
Grave_Location, Email, Phone, Adress, Bio, Travail, Photo, Fete) VALUES 
('$ID','$Family_ID','$First_Name','$Last_Name','$Gender','$Birthday','$Birthplace',
'$Father_ID','$Mother_ID','$Maiden_Name','$Mariage_ID','$Deathdate','$Deathplace',
'$Grave_Location','$Email','$Phone','$Address','$Bio','$Travail','$Photo','$Fete')";

mysql_query($query) or die ("Error updating database");

mysql_error();
mysql_close();

All i get in return is:

Connected to MySQLError updating database

whats wrong? (i HAVE done my research, over 2 days fyi)
im sorry that im new to this, cant help it

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1 Answer

  1. Editorial Team

    Your first approach looks fine, but for security reasons fetch the posted variables like below $ID=mysql_real_escape_string($_POST['ID']);
    mysql_real_escape_string() method will remove the unwanted characters and makes it secure.

    At the end try to print the query which you are executing using echo or print statement.

    echo $query;

    Execute the result on your phpmyadmin. Phpmyadmin will let you know what are the errors in your mysql query and following those instructions you can change your query.

    Debugging can be done by printing the results after each line execution wherever you feel something is going wrong.

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