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Home/ Questions/Q 6900683
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Editorial Team
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Editorial Team
Asked: May 27, 20262026-05-27T07:34:37+00:00 2026-05-27T07:34:37+00:00

I have following markup, <div custom=> <div> <template> <a custom=> (anything inside template should

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I have following markup,

<div custom="">
  <div>
     <template>
        <a custom="">  (anything inside template should not be selected)
        </a>
     </template> 
  </div>
</div>

<a custom=""></a>

I want to select all element that has custom attribute but not anything that is inside “template” node.

I have tried following but does not work,

$(":not(template *) [custom]")
$(":not(template) [custom]")
$(":not(template) *[custom]")
$(":not(template *)[custom]")
$(":not(template)").filter('[custom]')) // this does not work either...
$(":not(template,template *)").filter('[custom]')) // this does not work either...

But this does not work. Any simpler way to do this? I am not getting any elements in query.

I know, template is not a standard html. But its my custom tag to have proper tag within html instead of wrapping in non standard script where markup validation is not possible.

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  1. Editorial Team
    Editorial Team
    2026-05-27T07:34:38+00:00Added an answer on May 27, 2026 at 7:34 am

    Give this a shot.

    $('[custom]:not(template *)');
    

    jsFiddle.

    This selects all elements with a custom attribute (including descendants of template), and then throws away the elements which are a descendant of a template element.

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