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Home/ Questions/Q 6566431
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Editorial Team
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Editorial Team
Asked: May 25, 20262026-05-25T14:12:58+00:00 2026-05-25T14:12:58+00:00

i have following simpled algorithm for calculation roots of quadratic equation #include <iostream> #include

  • 0

i have following simpled algorithm for calculation roots of quadratic equation

#include <iostream>
#include <math.h>
using namespace std;
int main(){
    float x,x1;
    x=0;x1=0;
    int a=1;
    int b;
    int c;
    cout<<"enter the second term:"<<endl;
    cin>>b;
    cout<<"enter the third term:";
    cin>>c;
    float d=b^2-4*a*c;
      if (d<0){

          cout<<"the equation  has not real solution :"<<endl;
              }


      else   if (d==0) {  x=(-b/2); x1=x;}
      else
      {
          x=(-b+sqrt(d))/2;x1=(-b-sqrt(d))/2;


      }
      cout<<"roots are :"<<x<< " "<<x1<< "  "<<endl;



    return 0;
}

but it gives me warning

arning C4244: '=' : conversion from 'int' to 'float', possible loss of data

and when i enter -6 and 9 it gives that roots are 6 and zero which of course is not true please help me

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  1. Editorial Team
    Editorial Team
    2026-05-25T14:12:59+00:00Added an answer on May 25, 2026 at 2:12 pm

    ^ is the bitwise xor operator, not the power, as you probably think. To raise a number to an arbitrary power, use std::pow (from the standard header cmath). For powers of two, you can just use x * x.

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