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Home/ Questions/Q 8012551
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Editorial Team
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Editorial Team
Asked: June 4, 20262026-06-04T19:21:41+00:00 2026-06-04T19:21:41+00:00

i have following variable. i only want to print yes if the variable has

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i have following variable. i only want to print yes if the variable has “imoport/canada/campingplaces/tobermory” not # or anything. What should insert in a regex for this kind of things.

  my $textfile = "# imoport/canada/campingplaces/tobermory
                    imoport/canada/campingplaces/tobermory
                  #imoport/canada/campingplaces/tobermory";
  my $textNeeded= "imoport/canada/campingplaces/tobermory"

THIS IS WHAT i am using

  if ($textfile =~ m/$textNeeded/i) {
       print "yes working"

  }

note:- i am getting data from differnt text files so some text files might just have “#imoport/canada/campingplaces/tobermory”. I want to avoid those

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  1. Editorial Team
    Editorial Team
    2026-06-04T19:21:42+00:00Added an answer on June 4, 2026 at 7:21 pm

    Despite the quite vague problem description, I think I have puzzled out what you mean. You mean you may have lines where the text is commented out with #, and you want to avoid matching those.

    print "yes" if $textfile =~ /^\s*$textNeeded/im;
    

    This will match any string inside $textfile which has a newline followed by optional whitespace followed by your string. The /m option makes the regex multiline, meaning that ^ and $ match line endings represented by newlines inside a larger string.

    You may wish to be wary of regex meta characters in your search string. If for example your search string is foo[bar].txt, those brackets will be interpreted as a character class instead. In which case you would use

    /^\s*\Q$textNeeded\E/im
    

    instead. The \Q ... \E will make the text inside match only literal characters.

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