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Home/ Questions/Q 8418667
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Editorial Team
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Editorial Team
Asked: June 10, 20262026-06-10T02:23:35+00:00 2026-06-10T02:23:35+00:00

I have interface based on another: class IDrawable { public: virtual ~IDrawable(); }; class

  • 0

I have interface based on another:

class IDrawable {
public:
   virtual ~IDrawable();
};

class IExtendedDrawable: public IDrawable {
public:
   virtual ~IExtendedDrawable();
};

class DrawableImplementation: public IDrawable {
public:
   virtual ~DrawableImplementation();
};

class ExtendedDrawableImplementation: 
   public DrawableImplementation, public IExtendedDrawable
{
public:
   virtual ~ExtendedDrawableImplementation();
};

Then ExtendedDrawableImplementation = DrawableImplementation (+IDrawable) + IExtendedDrawable (+IDrawable)

Is it right to have IDrawable twice in same class?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-10T02:23:37+00:00Added an answer on June 10, 2026 at 2:23 am

    I’ll give the benefit of the doubt that you DO indeed need/want multiple inheritance. I see it as good in only limited situations, and interfaces is one of them (even Java allows this).

    As said above, use virtual inheritance and be sure to only use pure virtual methods in the interface classes.

    class IDrawable {
    public:
       virtual ~IDrawable();
       virtual void doSomething() = 0;
    };
    
    class IExtendedDrawable: virtual public IDrawable {
    public:
       virtual ~IExtendedDrawable();
       virtual void doSomethingElse() = 0;
    };
    
    class DrawableImplementation: virtual public IDrawable {
    public:
       virtual ~DrawableImplementation();
       virtual void doSomething() {/*code here*/}
    };
    
    class ExtendedDrawableImplementation: 
       public DrawableImplementation, public IExtendedDrawable
    {
    public:
       virtual ~ExtendedDrawableImplementation();
       virtual void doSomething() {/*code here*/}
       virtual void doSomethingElse() {/*code here*/}
    };
    
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