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Editorial Team
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Editorial Team
Asked: May 15, 20262026-05-15T23:45:33+00:00 2026-05-15T23:45:33+00:00

I have made my application universal for iPhone and iPad (window-based application; universal) from

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I have made my application universal for iPhone and iPad (window-based application; universal) from scratch.
First I made all logic and views for iPhone and it worked. After that I created views for iPad. That worked to. But when I implemented UISplitViewController or UIPopover, the application will not build anymore for iPhone.

I call my custom splitViewController like that:

MySplitViewController *mySplitViewController = [[MySplitViewController" alloc] init];

Class definition looks like that:
@interface MySplitViewController : UISplitViewController {
}

On build (for iPhone 3.1.3) it gives me this error:

cannot find interface declaration for
‘UISplitViewController’, superclass of
‘MySplitViewController’

Afcourse, SDK 3.1.3 does not contain all new features from SDK 3.2. That’s clear. So I tried creating instance of my class like that:

MySplitViewController *mySplitViewController = [[NSClassFromString(@"MySplitViewController") alloc] init];

It still gives me the same error.

I also tried to weak-link framework but that helped neither.

What I also tried is that I wrap creating instance of class in parentheses like that:

Class cls = NSClassFromString(@"UIPopoverController");
if (cls != nil) {
    MySplitViewController *mySplitViewController = [[NSClassFromString(@"MySplitViewController") alloc] init];
}

Could please someone tells me how can I call specific classes so I can run my application for both platform ?

Thanks

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  1. Editorial Team
    Editorial Team
    2026-05-15T23:45:34+00:00Added an answer on May 15, 2026 at 11:45 pm

    I have found the solution here.

    I hope it will helps someone else…

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