Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • SEARCH
  • Home
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 951587
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: May 15, 20262026-05-15T23:45:33+00:00 2026-05-15T23:45:33+00:00

I have made my application universal for iPhone and iPad (window-based application; universal) from

  • 0

I have made my application universal for iPhone and iPad (window-based application; universal) from scratch.
First I made all logic and views for iPhone and it worked. After that I created views for iPad. That worked to. But when I implemented UISplitViewController or UIPopover, the application will not build anymore for iPhone.

I call my custom splitViewController like that:

MySplitViewController *mySplitViewController = [[MySplitViewController" alloc] init];

Class definition looks like that:
@interface MySplitViewController : UISplitViewController {
}

On build (for iPhone 3.1.3) it gives me this error:

cannot find interface declaration for
‘UISplitViewController’, superclass of
‘MySplitViewController’

Afcourse, SDK 3.1.3 does not contain all new features from SDK 3.2. That’s clear. So I tried creating instance of my class like that:

MySplitViewController *mySplitViewController = [[NSClassFromString(@"MySplitViewController") alloc] init];

It still gives me the same error.

I also tried to weak-link framework but that helped neither.

What I also tried is that I wrap creating instance of class in parentheses like that:

Class cls = NSClassFromString(@"UIPopoverController");
if (cls != nil) {
    MySplitViewController *mySplitViewController = [[NSClassFromString(@"MySplitViewController") alloc] init];
}

Could please someone tells me how can I call specific classes so I can run my application for both platform ?

Thanks

  • 1 1 Answer
  • 0 Views
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. Editorial Team
    Editorial Team
    2026-05-15T23:45:34+00:00Added an answer on May 15, 2026 at 11:45 pm

    I have found the solution here.

    I hope it will helps someone else…

    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Related Questions

I have to use a class/assembly made in C# .NET from native C++ application.
I have made a application and the logo appears on every page. All 3
I have made a custom UserControl i Vb.net (windows application). How can I add
I have made a SVG image, or more like mini application, for viewing graphs
I have an application that is made up of the following: A central database
I have an application where it was requested that a friendly url be made
I have converted an iPhone application using the wizard like thing in XCode into
I have made an application, which keeps getting updated frequently. So every time a
I have made an application (for my self) for feeds reading, using SyndicationFeed ,
I have made an application using Java/Hibernate/MySQL, but whenever I try running it, it

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.