Question

I have output like this:

LL= [['a', 2, 3, 4, 13], ['b', 6, 7, 8, 13], ['c', 10, 11, 12, 13]]

Instead of “13”, I would like to get maximum of elements by “row” using 2, 3 ,4

where [‘a’, 2, 3, 4, 13] would be 4
[‘b’, 6, 7, 8, 13], would be 8.

EDIT: I need to replace “13” with the max value.

Then add “14” after 13

for row in LL: row[5:6] = [14]

then replace “14” with a another inter row math..
How can I do this… these are tables but not matrices.
Should use Numpy?
Ref please so I can look up.

Answer 1

Is this in the directions what you are looking for?

LL= [['a', 2, 3, 4, 13], ['b', 6, 7, 8, 13], ['c', 10, 11, 12, 13]]

for row in LL:
    row[-1]= max(row[1: -1])
    row.append(14)
print LL

If not please describe more detailed manner your requirements.