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Home/ Questions/Q 3667146
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Editorial Team
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Editorial Team
Asked: May 19, 20262026-05-19T01:57:54+00:00 2026-05-19T01:57:54+00:00

I have piece of code: class example { public function say($x) { if ($x

  • 0

I have piece of code:

class example {
    public function say($x) {
        if ($x > 0) {
            echo $x;
            $this->say($x - 1);
        }
        else echo "0<br>\n";
    }
}

example::say(5);

Calling it I have:

 5
 Fatal error: Using $this when not in object context in (...).php on line 5

Why is this happening? What is happening to function ‘say’? I see it’s called once from outside a class, but why inside class PHP claims ‘say’ isn’t accesible by ‘$this->’?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-19T01:57:55+00:00Added an answer on May 19, 2026 at 1:57 am

    The error message is actually pretty clear: You cannot use $this, as you never created an instance of your example class. If you want to call your method statically, use this:

    class example {
        public static function say($x) {
            if ($x > 0) {
               echo $x;
               self::say($x - 1); // static call
           }
           else {
               echo "0<br>\n";
           }
       }
    }
    
    example::say(5);
    

    Or in a more object oriented way:

    class example {
        public function say($x) {
            if ($x > 0) {
               echo $x;
               $this->say($x - 1);
           }
           else {
               echo "0<br>\n";
           }
       }
    }
    
    $x = new example();
    $x->say(5);
    

    You can call a non-static method statically, but you shouldn’t (and this will only work if the method does not use $this). This is why PHP warns you if E_STRICT is enabled

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