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Home/ Questions/Q 7051555
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Editorial Team
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Editorial Team
Asked: May 28, 20262026-05-28T03:16:39+00:00 2026-05-28T03:16:39+00:00

I have query like this: SELECT `all_messages`.`user_1`, `messages`.*, `users`.`username` FROM `all_messages` JOIN `messages` ON

  • 0

I have query like this:

SELECT `all_messages`.`user_1`, `messages`.*, `users`.`username` 
FROM `all_messages` 
JOIN `messages` ON (`all_messages`.`user_2` = `messages`.`from_user`) 
JOIN `users` ON (`all_messages`.`user_2` = `users`.`id`)
WHERE `all_messages`.`user_1` = '12' 
ORDER BY `messages`.`sent` DESC LIMIT 2

Now this query does what I need but my problem is with this line

ON (`all_messages`.`user_2` = `messages`.`from_user`)

It selects all data from messages where the matches was found but I need only one newest record. I hope you guys get what I mean.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-28T03:16:39+00:00Added an answer on May 28, 2026 at 3:16 am

    If you need one “newest record” you should have a date column or something, lets name it "CREATION_TIME", so you could do something like this

    SELECT AM.user_1, M.*, U.username 
    FROM all_messages AM, messages M , users U
    WHERE AM.user_1 = '12' 
    AND  AM.user_2 = M.from_user
    AND  AM.user_2 = U.id
    AND M.CREATION_TIME =
    ( 
      SELECT MAX(CREATION_TIME)
      FROM messages 
      WHERE from_user= M.from_user
    )
    ORDER BY M.sent DESC LIMIT 2
    

    Edit

        SELECT AM.user_1, M.*, U.username 
        FROM all_messages AM, messages M, users U
        WHERE AM.user_1 = '12' 
        AND  AM.user_2 = M.from_user
        AND  AM.user_2 = U.id
        AND M.sent =
        ( 
          SELECT MAX(sent)
          FROM messages 
          WHERE from_user= M.from_user
        )
        ORDER BY M.sent DESC LIMIT 2
    

    It should work

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