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Home/ Questions/Q 8616211
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Editorial Team
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Editorial Team
Asked: June 12, 20262026-06-12T05:33:50+00:00 2026-06-12T05:33:50+00:00

I have query like this: SELECT DATE,REGION,COUNT(*) FROM ALL_ID_DATA WHERE DATE in (SUBDATE(CURDATE(),1),SUBDATE(CURDATE(),2),SUBDATE(CURDATE(),8)) AND

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I have query like this:

SELECT DATE,REGION,COUNT(*)
FROM ALL_ID_DATA
WHERE DATE in (SUBDATE(CURDATE(),1),SUBDATE(CURDATE(),2),SUBDATE(CURDATE(),8))
AND DIRECTION='inbound'
AND REASON_1 = 'complaint'
GROUP BY REGION,DATE DESC

and the result is
capture
What is the right query to display like this capture below

result
Could somebody help me?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-12T05:33:51+00:00Added an answer on June 12, 2026 at 5:33 am

    This type of query is known as a PIVOT. Unfortunately, MySQL doesn’t have a PIVOT function, so you will need to replicate the function using a CASE statement and an aggregate function.

    If you know the number of columns to transform, then you can hard-code the values:

    select region,
      SUM(CASE WHEN date = '2012-09-24' THEN 1 END) as `2012-09-24`,
      SUM(CASE WHEN date = '2012-09-30' THEN 1 END) as `2012-09-30`,
      SUM(CASE WHEN date = '2012-10-01' THEN 1 END) as `2012-10-01`
    from ALL_ID_DATA
    group by region;
    
    select region,
      COUNT(CASE WHEN date = '2012-09-24' THEN 1 ELSE null END) as `2012-09-24`,
      COUNT(CASE WHEN date = '2012-09-30' THEN 1 ELSE null END) as `2012-09-30`,
      COUNT(CASE WHEN date = '2012-10-01' THEN 1 ELSE null END) as `2012-10-01`
    from ALL_ID_DATA
    group by region;
    

    See SQL Fiddle with Demo.

    Then adding this to your existing query, it would be:

    SELECT REGION,
      SUM(CASE WHEN date = '2012-09-24' THEN 1 END) as `2012-09-24`,
      SUM(CASE WHEN date = '2012-09-30' THEN 1 END) as `2012-09-30`,
      SUM(CASE WHEN date = '2012-10-01' THEN 1 END) as `2012-10-01`
    FROM ALL_ID_DATA
    WHERE DATE in (SUBDATE(CURDATE(),1),SUBDATE(CURDATE(),2),SUBDATE(CURDATE(),8))
      AND DIRECTION='inbound'
      AND REASON_1 = 'complaint'
    GROUP BY REGION
    

    OR

    SELECT REGION,
      COUNT(CASE WHEN date = '2012-09-24' THEN 1 ELSE null END) as `2012-09-24`,
      COUNT(CASE WHEN date = '2012-09-30' THEN 1 ELSE null END) as `2012-09-30`,
      COUNT(CASE WHEN date = '2012-10-01' THEN 1 ELSE null END) as `2012-10-01`
    FROM ALL_ID_DATA
    WHERE DATE in (SUBDATE(CURDATE(),1),SUBDATE(CURDATE(),2),SUBDATE(CURDATE(),8))
      AND DIRECTION='inbound'
      AND REASON_1 = 'complaint'
    GROUP BY REGION
    

    Now if you have an unknown number of dates to transform into columns, then you can use prepared statements and your query would be similar to this (See SQL Fiddle with Demo):

    SET @sql = NULL;
    SELECT
      GROUP_CONCAT(DISTINCT
        CONCAT(
          'sum(case when date = ''',
          date,
          ''' then 1 else 0 end) AS ''',
          Date(date), ''''
        )
      ) INTO @sql
    FROM ALL_ID_DATA;
    
    select @sql;
    
    SET @sql = CONCAT('SELECT region, ', @sql, ' 
                       FROM ALL_ID_DATA
                       GROUP BY region');
    
    PREPARE stmt FROM @sql;
    EXECUTE stmt;
    DEALLOCATE PREPARE stmt;
    

    Then placing your original query in the prepared statement the final query would be:

    SET @sql = NULL;
    SELECT
      GROUP_CONCAT(DISTINCT
        CONCAT(
          'sum(case when date = ''',
          date,
          ''' then 1 else 0 end) AS ''',
          Date(date), ''''
        )
      ) INTO @sql
    FROM ALL_ID_DATA;
    
    select @sql;
    
    SET @sql = CONCAT('SELECT region, ', @sql, ' 
                       FROM ALL_ID_DATA
                       WHERE DATE in (SUBDATE(CURDATE(),1),SUBDATE(CURDATE(),2),SUBDATE(CURDATE(),8))
                       AND DIRECTION=''inbound''
                       AND REASON_1 = ''complaint''');
    
    PREPARE stmt FROM @sql;
    EXECUTE stmt;
    DEALLOCATE PREPARE stmt;
    
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