Question

I have seen this thread already – How can I unshorten a URL?

My issue with the resolved answer (that is using the unshort.me API) is that I am focusing on unshortening youtube links. Since unshort.me is used readily, this returns almost 90% of the results with captchas which I am unable to resolve.

So far I am stuck with using:

def unshorten_url(url):
    resolvedURL = urllib2.urlopen(url)  
    print resolvedURL.url

    #t = Test()
    #c = pycurl.Curl()
    #c.setopt(c.URL, 'http://api.unshort.me/?r=%s&t=xml' % (url))
    #c.setopt(c.WRITEFUNCTION, t.body_callback)
    #c.perform()
    #c.close()
    #dom = xml.dom.minidom.parseString(t.contents)
    #resolvedURL = dom.getElementsByTagName("resolvedURL")[0].firstChild.nodeValue
    return resolvedURL.url

Note: everything in the comments is what I tried to do when using the unshort.me service which was returning captcha links.

Does anyone know of a more efficient way to complete this operation without using open (since it is a waste of bandwidth)?

Answer 1

Use the best rated answer (not the accepted answer) in that question:

# This is for Py2k.  For Py3k, use http.client and urllib.parse instead, and
# use // instead of / for the division
import httplib
import urlparse

def unshorten_url(url):
    parsed = urlparse.urlparse(url)
    h = httplib.HTTPConnection(parsed.netloc)
    resource = parsed.path
    if parsed.query != "":
        resource += "?" + parsed.query
    h.request('HEAD', resource )
    response = h.getresponse()
    if response.status/100 == 3 and response.getheader('Location'):
        return unshorten_url(response.getheader('Location')) # changed to process chains of short urls
    else:
        return url