Question

I have some xml:

<item name="ed" test="true"
  xmlns="http://www.somenamespace.com"
  xmlns:xsi="http://www.somenamespace.com/XMLSchema-instance">
  <blah>
     <node>value</node>
  </blah>
</item>

I want to go through this xml and remove all namespaces completely, no matter where they are. How would I do this with Scala?

 <item name="ed" test="true">
  <blah>
     <node>value</node>
  </blah>
</item>

I’ve been looking at RuleTransform and copying over attributes etc, but I can either remove the namespaces or remove the attributes but not remove the namespace and keep the attributes.

Answer 1

The tags are Elem objects and the namespace is controlled by the scope value. So to get rid of it you could use:

xmlElem.copy(scope = TopScope)

However this is an immutable recursive structure so you need to do this in a recursive manner:

import scala.xml._

def clearScope(x: Node):Node = x match {
  case e:Elem => e.copy(scope=TopScope, child = e.child.map(clearScope))
  case o => o
}

This function will copy the XML tree removing the scope on all the nodes. You may have to remove the scope from the attributes too.