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Home/ Questions/Q 9007559
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Editorial Team
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Editorial Team
Asked: June 16, 20262026-06-16T01:43:23+00:00 2026-06-16T01:43:23+00:00

I have something like this: class A { void add (A* a) { //add

  • 0

I have something like this:

class A {
    void add (A* a) {
        //add a to a vector<A*>
    }
    virtual void draw() = 0;
}

class B : public A {
    void tick() {}
    void draw() {}
}

class C : public A {
    void draw() {}
}

Now what I want to do is have a loop like this:

for(int i=0; i<vector.size(); i++) {
    vector[i]->tick();
}

Problem is that not all the elements in this vector will have the tick() method, but I still want to have them in the same vector because I also want to be able to loop through the vector and call draw() on all the elements. Is there some way to solve this? I’m considering having another vector but I’d rather not.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-16T01:43:24+00:00Added an answer on June 16, 2026 at 1:43 am

    If you have a vector of widgets, but only some of those widgets have a dingbat, are they really all widgets?

    In your case you have a vector of things that aren’t the same. This is your problem. Sure, you could come up with some hacky, complex mechanism to put a battleship in a pencil cup. Or you could do what I’d consider to be one of the Right Things:

    1. Make sure everything you’re putting in to the pencil cup is a pencil
    2. Create someplace else to put the battleship.

    Number 2 above is creating a seperate vector as you’ve already mentioned. Number 1 might be as simply as providing a virtual tick() method with an empty (trivial) implementation on the base class.

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