Question

I have the following Abstract:

class A:
    clientname ...
    logs = models.ManyToManyField(B, blank=True, null=True)

class B.
    message ...
    timestamp =  models.DateTimeField()

    def save(self, *args, **kwargs):
        self.timestamp = datetime.now()
        super(B, self).save(*args, **kwargs)

Now, if a message is saved I want it to have a timestamp, always. And I do not want to change the many2many relationship. Is this possible? And if It is how would I go about writing it?

UPDATE:

my view

def log(request):
    if request.method == 'POST':
        log, created = B.objects.get_or_create(message=request.POST['message'])
        client = \
            A.objects.get(clientname=request.POST['clientname'])
        client.logs.add(log)
        return HttpResponse(content="OK", mimetype="text/plain", status=200)
    else:
        return HttpResponse(content="Failed", mimetype="text/plain", status=400)

RESOLUTON:
I did it, this is kind of a workaround:

def log(request):
    if request.method == 'POST':
        time = datetime.now()
        log, created = \
            Log.objects.get_or_create(message=request.POST['message'], \
            timestamp=time)
        client = \
            Thinclient.objects.get(hostname=request.POST['clientname'])
        client.logs.add(log)
        return HttpResponse(content="OK", mimetype="text/plain", status=200)
    else:
        return HttpResponse(content="Failed", mimetype="text/plain", status=400)

UPDATE:

No actually that wasn’t what I wanted either because this will create new message instances even if the message is the same

Answer 1

add save() to the class B

def save(self, *args, **kwargs):
    self.timestamp = datetime.now()
    super(B, self).save(*args, **kwargs)