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Home/ Questions/Q 3492074
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Editorial Team
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Editorial Team
Asked: May 18, 20262026-05-18T11:42:51+00:00 2026-05-18T11:42:51+00:00

I have the following block of code that works just fine: <%@page import="java.util.*" %>

  • 0

I have the following block of code that works just fine:

<%@page import="java.util.*" %>
<%@page import="java.security.*" %>

<%
String str = "A string to hash.";
MessageDigest md = MessageDigest.getInstance("MD5");
md.update( str.getBytes() );
byte[] digest = md.digest();
StringBuffer hexString = new StringBuffer();
for (int i = 0, j = digest.length; i < j; i++) {
    String tmp = Integer.toHexString(0xFF & digest[i]);
    if (tmp.length() < 2) {
        tmp = "0" + tmp;
    }

    hexString.append(tmp);
}

out.println(hexString.toString());
%>

When I tried to break the hashing code out into a method I got a “NoSuchAlgorithmException” error when defining the MessageDigest object:

<%@page import="java.util.*" %>
<%@page import="java.security.*" %>

<%
String str = "A string to hash";
String md5string = md5hash(str);

out.println(md5string);
%>

<%!
public String md5hash(String str) {
    MessageDigest md = MessageDigest.getInstance("MD5");

    md.update( str.getBytes() );
    byte[] digest = md.digest();
    StringBuffer hexString = new StringBuffer();
    for (int i = 0, j = digest.length; i < j; i++) {
        String tmp = Integer.toHexString(0xFF & digest[i]);
        if (tmp.length() < 2) {
            tmp = "0" + tmp;
        }

        hexString.append(tmp);
    }

    return hexString.toString();
}
%>

To get the JSP to compile, I had to modify it like so:

<%@page import="java.util.*" %>
<%@page import="java.security.*" %>

<%
String str = "A string to hash";
String md5string = md5hash(str);

out.println(md5string);
%>

<%!
public String md5hash(String str) {
    MessageDigest md = null;

    try {
        md = MessageDigest.getInstance("MD5");
    } catch (NoSuchAlgorithmException e) {}

    md.update( str.getBytes() );
    byte[] digest = md.digest();
    StringBuffer hexString = new StringBuffer();
    for (int i = 0, j = digest.length; i < j; i++) {
        String tmp = Integer.toHexString(0xFF & digest[i]);
        if (tmp.length() < 2) {
            tmp = "0" + tmp;
        }

        hexString.append(tmp);
    }

    return hexString.toString();
}
%>

Why did I have to add a useless try/catch to make this code work?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-18T11:42:52+00:00Added an answer on May 18, 2026 at 11:42 am

    The normal JSP source code is by itself already placed in one huge try-catch block. Every normal scriptlet <% %> will become part of it, so you don’t need to explicitly catch the exceptions. However, a method definition <%! %> will be placed outside the standard try-catch, so you have to handle the exceptions yourself.

    Needless to say that this is not the best practice. Rather put the Java code in a real Java class. For this particular purpose, I think an EL function is very useful. See also How to avoid Java code in JSP files?

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