Question

I have the following C++ classes.

xyz.h

class xyz {
public:
    static int abc();
};

qwe.h

#include xyz.h

namespace xyz {

class qwe{
public:
    void bnm() {
        int value = xyz::abc();

    }
};

}

How do I access xyz::abc() here. I get a compilation error here saying abc is not a member of xyz. I understand the reason that it’s trying to search for the abc method inside this xyz namespace whereas what it should ideally get is a static method in the xyz class.

Is there a way to get around this without changing the namespace names?

Answer 1

Don’t make a class with the same name as a namespace (or its own namespace for that matter).