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Asked: May 11, 20262026-05-11T12:23:07+00:00 2026-05-11T12:23:07+00:00

I have the following code: const string Sql = @select distinct [name] from tblCustomers

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I have the following code:

const string Sql =      @'select distinct [name]        from tblCustomers        left outer join tblCustomerInfo on tblCustomers.Id = tblCustomerInfo.CustomerId         where (tblCustomer.Name LIKE '%@SEARCH%' OR tblCustomerInfo.Info LIKE '%@SEARCH%');';  using (var command = new SqlCommand(Sql, Connection)) {            command.Parameters.AddWithValue('@SEARCH', searchString);     ... } 

This does not work, I tried this as well:

const string Sql =      @'select distinct [name]       from tblCustomers       left outer join tblCustomerInfo on tblCustomers.Id = tblCustomerInfo.CustomerId        where (tblCustomer.Name LIKE @SEARCH OR tblCustomerInfo.Info LIKE @SEARCH );';  using (var command = new SqlCommand(Sql, Connection)) {            command.Parameters.AddWithValue('@SEARCH', ''%' + searchString + '%'');     ... } 

but this does not work as well. What is going wrong? Any suggestions?

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  1. 2026-05-11T12:23:08+00:00Added an answer on May 11, 2026 at 12:23 pm

    What you want is:

    tblCustomerInfo.Info LIKE '%' + @SEARCH + '%' 

    (or edit the parameter value to include the % in the first place).

    Otherwise, you are either (first sample) searching for the literal ‘@SEARCH’ (not the arg-value), or you are embedding some extra quotes into the query (second sample).

    In some ways, it might be easier to have the TSQL just use LIKE @SEARCH, and handle it at the caller:

    command.Parameters.AddWithValue('@SEARCH','%' + searchString + '%'); 

    Either approach should work.

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