Question

I have the following code

date("D j M g a", strtotime($start))." - " . date("ga", strtotime($finish));


`["Start"]=>
        string(21) "/Date(1354323600000)/"
        ["End"]=>
        string(21) "/Date(1354326300000)/"
      }`

The above code outputs Thu 1 Jan 12 pm - 12pm" string(22) "Thu 1 Jan 12 pm - 12pm in the correct format that I want but how could I get the day date and time correct.

Pacific/Auckland is my timezone

Answer 1

The issue is that what you pass to the strtotime – /Date(1354323600000)/ string is not in a valid format for strtotime function.

And actually it’s a regular unix timestamp in milliseconds.

So the obvious solution – is to clean up everything but numbers and divide it by 1000:

$unix_time_with_ms = preg_replace('~\D~', '', $date);
echo date('Y-m-d H:i:s', $unix_time_with_ms / 1000);