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Home/ Questions/Q 7540311
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Editorial Team
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Editorial Team
Asked: May 30, 20262026-05-30T07:36:42+00:00 2026-05-30T07:36:42+00:00

I have the following code: def subStringMatchExact(target,key,matches=(),base=0): if find(target,key) != -1: matches += (find(target,key)+base,)

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I have the following code:

def subStringMatchExact(target,key,matches=(),base=0):
    if find(target,key) != -1:
        matches += (find(target,key)+base,)
        base += find(target,key)+len(key)
        subStringMatchExact(target[find(target,key)+len(key):],key,matches,base)
    else:
        print matches
        return matches

When I run the function, say for instance subStringMatchExact('abcdabcdababcdedakcdobcdabcd','abc'), the print matches line will have my interpreter print (0,4,10,24), which is correct. However the line return matches returns value None.

Similarly when I call print subStringMatchExact('abcdabcdababcdedakcdobcdabcd','abc'), the interpreter also gives None.

Can anyone help me correct this?

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  1. Editorial Team
    Editorial Team
    2026-05-30T07:36:43+00:00Added an answer on May 30, 2026 at 7:36 am

    I rather think that you intended to return the recursive value on line 5. As it is, it just calls it and then continues to the end of the method, returning None. So, all you need is the insertion of the return keyword.

    def subStringMatchExact(target,key,matches=(),base=0):
        if find(target,key) != -1:
            matches += (find(target,key)+base,)
            base += find(target,key)+len(key)
            return subStringMatchExact(target[find(target,key)+len(key):],key,matches,base)
        else:
            print matches
            return matches
    
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