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Home/ Questions/Q 7990429
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Editorial Team
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Editorial Team
Asked: June 4, 20262026-06-04T13:00:26+00:00 2026-06-04T13:00:26+00:00

I have the following code. Given that the variable u1 can be any of

  • 0

I have the following code. Given that the variable u1 can be any of the following:

NBSLoan|Accept|PPI+No|60Months
NBSLoan|Refer|PPI+No|60Months
DeBSLoan|Accept|PPI+No|60Months

Also, the last part 60Months will always be different, can I pattern match using the following JavaScript? Do I need to put in a special character for the pipe | symbol? Or will this not work as I’m trying to match only the first part of a longer string?

<script type="text/javascript">
var u1 = 'NBSLoan|Accept|PPI+No|60Months';

var n_accept = /^NBSLoan|Accept$/;
var n_refer = /^NBSLoan|Refer$/;
var d_accept = /^DeBSLoan|Accept$/;

if (u1.match(n_accept)) {       
var pvnPixel = '<img src="https://url1.com"/>';
document.write(pvnPixel);
}
else if (u1.match(n_refer)) {       
var pvnPixel2 = '<img src="url2.com"/>';
document.write(pvnPixel2);
}
else if (u1.match(d_accept)) {
var pvnPixel3 = '<img src="url3.com"/>';
document.write(pvnPixel3);  
}
</script>
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-04T13:00:28+00:00Added an answer on June 4, 2026 at 1:00 pm

    Do I need to put in a special character for the pipe | symbol? Or will this not work as I’m trying to match only the first part of a longer string?

    Both.

    • You need to escape the pipe symbol with a backslash to match a literal pipe character. Without the backslash it means alternation.
    • You also need to remove your end of line anchor.

    Try this regular expression:

    /^NBSLoan\|Accept/
    
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