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Home/ Questions/Q 812731
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Editorial Team
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Editorial Team
Asked: May 15, 20262026-05-15T01:14:53+00:00 2026-05-15T01:14:53+00:00

I have the following code in some app: int lowRange=50; int[] ageRangeIndividual = {6,

  • 0

I have the following code in some app:

int lowRange=50;
int[] ageRangeIndividual = {6, 10, 18, 25, 45, 65, 90};
int index=0;
for (; index<ageRangeIndividual.length-1 && ageRangeIndividual[index]<=lowRange;index++);

I am getting an “Exception in thread “main” java.lang.ArrayIndexOutOfBoundsException: 7″ in the for line! even though I explicitly specify to break the cycle if index < last indexable item in the array!

This does not happen always, but after some time of running said program (lowRange varies each time the function is called)

What am I not seeing?

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  1. Editorial Team
    Editorial Team
    2026-05-15T01:14:54+00:00Added an answer on May 15, 2026 at 1:14 am

    The code you’ve posted doesn’t throw an exception, on its own. In fact, your array bounds check is one off – you’re being too conservative, unless you really don’t intend to check the last value. It would normally just be

    index < ageRangeIndividual.length
    

    You say it happens eventually – do you have any other threads changing the value of index or ageRangeIndividual?

    I presume you’re about to use index in the next line – personally I’d find it clearer if this were wrapped up in a method:

    // Rename to something more appropriate, perhaps
    public static int findIndexOverMinimum(int[] values, int minimum)
    {
        for (int i = 0; i < values.length; i++)
        {
            if (values[i] > minimum)
            {
                return i;
            }
        }
        return -1; // Or throw an exception, whichever is most appropriate
    }
    

    I really don’t like for loops which have no body, and which use an existing variable for indexing. It’s all perfectly valid, but it just feels wrong.

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