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Home/ Questions/Q 6603813
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Editorial Team
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Editorial Team
Asked: May 25, 20262026-05-25T19:03:57+00:00 2026-05-25T19:03:57+00:00

I have the following code (simplified to see the logic behind): <div id=alfa>Text <script>

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I have the following code (simplified to see the logic behind):

<div id="alfa">Text
    <script>
        $("#alfa").click(function() {
            alert($(this).attr("id"));
        });
    </script>
</div>
<script>
    var clone = $("#alfa").clone().attr("id",$("#alfa").attr("id")+"_1");
    $("#alfa").after(clone);
</script>

I need to see “alfa_1” when I click in the cloned Text, but nothing happens.

When I use clone(true,true) that works, but I don’t see the code of the cloned div in Firebug to see what really happens.

Also I don’t know why clicking the original div the alert is triggered twice.

Thanks.

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  1. Editorial Team
    Editorial Team
    2026-05-25T19:03:57+00:00Added an answer on May 25, 2026 at 7:03 pm

    I need to see “alfa_1” when I click in the cloned Text, but nothing happens.

    Doing DOM or innerHTML manipulations on <script> elements is inconsistent in browsers and doesn’t really make any sense in terms of the JavaScript execution cycle. Avoid it in all cases.

    If you want to copy DOM elements together with their jQuery event handlers, use clone(true):

    <div id="alfa">Text</div>
    
    <script type="text/javascript">
        $('#alfa').click(function() {
            alert(this.id);
        });
        var clone= $('#alfa').clone(true);
        clone[0].id+= '_1'; // sorry, I couldn't bring myself to do this the jQuery way
        $('#alfa').after(clone);
    </script>
    
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