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Home/ Questions/Q 8834831
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Editorial Team
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Editorial Team
Asked: June 14, 20262026-06-14T09:07:02+00:00 2026-06-14T09:07:02+00:00

I have the following function which gets called multiple times in my code: char*

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I have the following function which gets called multiple times in my code:

char* get_section_name(const char* section, const char* value) {

  char *tmp = (char *)malloc(STR_LEN * sizeof(char));

  if(strlen(section)>0) {

      strcat(tmp, section);

      strcat(tmp,".");

  }

  strcat(tmp, value);    

  return tmp;

}

and I call it in other functions like this:

section_name = get_section_name(data->model_name,"params_default");

What is the best way to free this memory? Can I just call free(section_name) when I am done?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-14T09:07:03+00:00Added an answer on June 14, 2026 at 9:07 am

    Yes free, however, you could consider a different name that makes it clear it is allocating memory. Also, you could make use of sprintf for combining 2 strings and strdup for just copying one.

    char* create_section_name(const char* section, const char* value) { 
      const int sectionLen = strlen(section);   
    
      if(sectionLen>0) {
          //+1 for the period and +1 for the null
          char *tmp = (char *)malloc((sectionLen + strlen(value) + 2) * sizeof(char));
          //do that often? consider a newString(size) macro. See below
          sprintf(tmp, "%s.%s", section, value);    
          return tmp;
      }
      else {    
        return strdup(value);
      }
    }
    

    This assumes you don’t need the full STR_LEN, it uses just enough in both cases.

    newString macro I suggested:

    #define newString(size) (malloc((size) * sizeof(char)))
    

    Or it can even automatically add one for the null:

    #define newString(size) (malloc(((size)+1) * sizeof(char)))
    

    Then malloc is replaced with this:

    char *tmp = newString(sectionLen + strlen(value) + 1); //+1 for period
    
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