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Home/ Questions/Q 499691
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Editorial Team
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Editorial Team
Asked: May 13, 20262026-05-13T06:00:41+00:00 2026-05-13T06:00:41+00:00

I have the following lines of code: sql = source C:\\My Dropbox\\workspace\\projects\\hosted_inv\\create_site_db.sql cursor.execute (sql)

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I have the following lines of code:

sql = "source C:\\My Dropbox\\workspace\\projects\\hosted_inv\\create_site_db.sql"
cursor.execute (sql)

When I execute my program, I get the following error:

Error 1064: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near ‘source C:\My Dropbox\workspace\projects\hosted_inv\create_site_db.sql’ at line 1

Now I can copy and past the following into mysql as a query:

source C:\\My Dropbox\\workspace\\projects\\hosted_inv\\create_site_db.sql

And it works perfect. When I check the query log for the query executed by my script, it shows that my query was the following:

source C:\\My Dropbox\\workspace\\projects\\hosted_inv\\create_site_db.sql

However, when I manually paste it in and execute, the entire create_site_db.sql gets expanded in the query log and it shows all the sql queries in that file.

Am I missing something here on how mysqldb does queries? Am I running into a limitation. My goal is to run a sql script to create the schema structure, but I don’t want to have to call mysql in a shell process to source the sql file.

Any thoughts? Thanks!

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  1. Editorial Team
    Editorial Team
    2026-05-13T06:00:41+00:00Added an answer on May 13, 2026 at 6:00 am

    As others said, you cannot use the command source in MySQLdb Python API

    So, instead of running that, load the file and execute it

    Lets say your .sql file has

    create database test;
    

    Read the content like

    sql=open("test.sql").read()
    

    And then execute it

    cursor.execute(sql);
    

    You will get new database “test”

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