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Home/ Questions/Q 521541
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Editorial Team
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Editorial Team
Asked: May 13, 20262026-05-13T08:15:39+00:00 2026-05-13T08:15:39+00:00

I have the following model: class A(models.Model): name = models.CharField(max_length=50) content_type = models.ForeignKey(ContentType) This

  • 0

I have the following model:

class A(models.Model):
    name = models.CharField(max_length=50)
    content_type = models.ForeignKey(ContentType)

This model is supposed to be the root model in some inheritance tree and content_type attribute is a kind of a hint about what type is really stored.
Obviously, I should calculate content_type transparently upon A instance creation. I think, in __init__. But there is a problem – there are two main contexts in which A instances are created:

  1. a = A(name='asdfdf') # here we must fill in content_type
  2. by QuerySet machinery with *args tuple. In this case I shouldn’t fill in content_type

So, I’m trying to write:

def __init__(self, *args, **kwargs):
    super(A, self).__init__(*args, **kwargs)
    if self.content_type is None: # << here is the problem
        self.content_type = ContentType.objects.get_for_model(self)

The thing is self.content_type is ReverseSingleRelatedObjectDescriptor instance with __get__ overriden so that it throws in case value is not set. Yes, I can do following:

def __init__(self, *args, **kwargs):
    super(A, self).__init__(*args, **kwargs)
    try: 
        self.content_type
    except Exception, v:
        self.content_type = ContentType.objects.get_for_model(self)

But I don’t like it. Is there a more ‘polite’ way to check if the ForeignKey attribute is set?

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  1. Editorial Team
    Editorial Team
    2026-05-13T08:15:40+00:00Added an answer on May 13, 2026 at 8:15 am

    Does it work if you examine self.content_type_id instead of self.content_type?

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