Question

I have the following perl script:

$myVariable = "some value";
//... some code ...
$myVariable =~ s/\+/ /g;
$myVariable =~s/%([a-fA-F0-9][a-fA-F0-9])/pack("C", hex($1))/seg;
//.. some more code ...

Reading from perl documentation, I think that =~ operator returns a boolean value, namely true or false.

My question is: Does the above operations where $myVariable is involved affect its value, or not.

N.B. The $myVariable‘s value is set in my script to a string that is a result from the $_ variable’s split. I think that should not affect the behavior of that operation.

P.S. If you need more code from my script just let me now.

Answer 1

$myVariable is changed, but because you are doing substitutions (s///), not because the result of a match or substitution is a boolean; =~ is not like =, it is like ==. If you want the boolean result of the action, you need to assign it.

$result = $myVariable =~ s/\+/ /g;