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Home/ Questions/Q 7911761
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Editorial Team
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Editorial Team
Asked: June 3, 20262026-06-03T13:22:01+00:00 2026-06-03T13:22:01+00:00

I have the following PHP code for one of my blocks <?php global $base_url;

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I have the following PHP code for one of my blocks

<?php global $base_url; ?>
<div class = "order-help">
<div class = "rc-img"><img src = "<?php print $base_url; ?>/sites/all/themes/businessconnect/images/contacts-box.jpg" alt = ""/></div>
</div>

This displays the image fine in my block but i also want to make the image a hyperlink to some other page. For that i used the following code

<?php global $base_url; ?>
<div class = "order-help">
<?php print( <a href="http://mylink.com/path/">
<div class = "rc-img">
<img src = "<?php print $base_url; ?>/sites/all/themes/businessconnect/images/contacts-box.jpg" alt = ""/></div>
</a>' ); ?>
</div>

But it does not work. What am i missing?
Please Help

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-03T13:22:02+00:00Added an answer on June 3, 2026 at 1:22 pm

    Just add an <a> tag to the HTML.

    <div class = "rc-img">
        <a href="http://mylink.com/path/">
            <img src="<?php print $base_url; ?>/sites/all/themes/businessconnect/images/contacts-box.jpg" alt=""/>
        </a>
    </div>
    

    Your code wasn’t working because print needs you to pass it a string, and you also had <?php print $base_url ?> inside of a <?php block.

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