Question

I have the following table:

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| id | capital_id | value |
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|  1 |          1 |     a |
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|  2 |          2 |     b |
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|  3 |          2 |     c |
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|  4 |          2 |     d |
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|  5 |          3 |     b |
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|  6 |          3 |     e |
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|  7 |          4 |     f |
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I need to select only distinct capital_id’s, but different from one that has a value given.

To be more clear, I’ll provide an example: If I have the record with id=5, I need to fetch all distinct capital_id’s, different than 3 and with the value different from ‘b’ (so capital_id’s to be fetched are: 1 and 4).

I managed to write the query like SELECT id FROM table WHERE capital_id != $capital_id AND value != $value, but duplicate capital_id’s are fetched this way. I tried to add a GROUP BY capital_id, but then capital_id=2 is also fetched, although one of its values is ‘b’.

How can I solve this problem?

Answer 1

SELECT capital_id 
FROM tableName
WHERE capital_id <> $capital_id
GROUP BY 1
HAVING SUM(value = $value) = 0