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Home/ Questions/Q 476297
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Editorial Team
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Editorial Team
Asked: May 13, 20262026-05-13T00:28:31+00:00 2026-05-13T00:28:31+00:00

I have the following XML: <a> <b> <d>D1 content (can include child nodes)</d> </b>

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I have the following XML:

<a>
    <b>
        <d>D1 content (can include child nodes)</d>
    </b>
    <b>
        <c>C1 content (can include child nodes)</c>
    </b>
    <b>
        <e>E1 content (can include child nodes)</e>
    </b>
    <b>
        <c>C2 content (can include child nodes)</c>
    </b>
</a>

Using XSLT 1.0, I need to produce from this simply: “cde”; i.e. a distinct list of the names of the immediate children of /a/b/ ordered by the node name. Each b has exactly one child of arbitrary name.

I can produce “ccde”:

<xsl:for-each select="/a/b/*">
    <xsl:sort select="name(.)"/>
    <xsl:value-of select="name(.)" />
</xsl:for-each>

I’ve tried using the usual preceding-sibling:: comparison, but as each b only has one child, the preceding sibling is always nothing.

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  1. Editorial Team
    Editorial Team
    2026-05-13T00:28:31+00:00Added an answer on May 13, 2026 at 12:28 am

    First add this key element to the top of your XSL:-

    <xsl:key name="tagNames" match="/a/b/*" use="name()" /> 
    

    Now your for each loop can look like this:-

    <xsl:template match="/*">
        <xsl:for-each select="/a/b/*[count(. | key('tagNames', name())[1]) = 1]">
            <xsl:sort select="name()" />
            <xsl:value-of select="name()" />
        </xsl:for-each>
    </xsl:template>
    
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