Question

I have the following XML:

<Field FieldRowId='1000'>     <Items>         <Item Name='CODE'/>         <Item Name='DATE'/>     </Items> </Field> 

I need to get the FieldRowId using OPENXML. The SQL i have so far:

INSERT INTO @tmpField       ([name], [fieldRowId]) SELECT [Name], --Need to get row id of the parent node  FROM OPENXML (@idoc, '/Field/Items/Item', 1)  

Answer 1

EDIT: I added a root node to the xml. and demonstrated grabbing the ID. I’m assuming you have more than one field element in the xml. This is assuming you have the starting XML; are you given an Item and have to traverse upwards?

DECLARE @T varchar(max)  SET @T =  '<root>     <Field FieldRowId='1000'>         <Items>             <Item Name='CODE'/>             <Item Name='DATE'/>         </Items>     </Field>     <Field FieldRowId='2000'>         <Items>             <Item Name='CODE'/>             <Item Name='DATE'/>         </Items>     </Field> </root>'  DECLARE @X xml  SET @X = CAST(@T as xml) SELECT Y.ID.value('../../@FieldRowId', 'int') as FieldID,         Y.ID.value('@Name', 'varchar(max)') as 'Name' FROM @X.nodes('/root/Field/Items/Item') as Y(ID)