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Asked: 2026-05-11T12:36:36+00:00

I have the following XML: <Field FieldRowId=1000> <Items> <Item Name=CODE/> <Item Name=DATE/> </Items> </Field>

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I have the following XML:

<Field FieldRowId='1000'>     <Items>         <Item Name='CODE'/>         <Item Name='DATE'/>     </Items> </Field>

I need to get the FieldRowId using OPENXML. The SQL i have so far:

INSERT INTO @tmpField       ([name], [fieldRowId]) SELECT [Name], --Need to get row id of the parent node  FROM OPENXML (@idoc, '/Field/Items/Item', 1)
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  1. EDIT: I added a root node to the xml. and demonstrated grabbing the ID. I’m assuming you have more than one field element in the xml. This is assuming you have the starting XML; are you given an Item and have to traverse upwards?

    DECLARE @T varchar(max)  SET @T =  '<root>     <Field FieldRowId='1000'>         <Items>             <Item Name='CODE'/>             <Item Name='DATE'/>         </Items>     </Field>     <Field FieldRowId='2000'>         <Items>             <Item Name='CODE'/>             <Item Name='DATE'/>         </Items>     </Field> </root>'  DECLARE @X xml  SET @X = CAST(@T as xml) SELECT Y.ID.value('../../@FieldRowId', 'int') as FieldID,         Y.ID.value('@Name', 'varchar(max)') as 'Name' FROM @X.nodes('/root/Field/Items/Item') as Y(ID)
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