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Home/ Questions/Q 6127019
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Editorial Team
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Editorial Team
Asked: May 23, 20262026-05-23T16:27:08+00:00 2026-05-23T16:27:08+00:00

I have this code : abstract class GenericAbstractClass<T> where T : struct { }

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I have this code :

abstract class GenericAbstractClass<T> where T : struct { }

class ImplementationClass : GenericAbstractClass<int> { }

class Program {
    static void Main (string[] args)
    {
        IKernel kernel = new StandardKernel();
            kernel.Bind(typeof(GenericAbstractClass<>)).To(typeof(ImplementationClass));

            var classes = kernel.GetAll(typeof(GenericAbstractClass<>));
            Console.WriteLine(classes.Count()); // Print 2.

            foreach (var cls in classes) {
                if (cls is ImplementationClass)
                    Console.WriteLine("cls is ImplementationClass");
            }


            Console.ReadLine();
        }
    }

The output is :

2
cls is ImplementationClass
cls is ImplementationClass

I expect classes.Count() result is 1.

Why GetAll return duplicate object despite of I only bind GenericClass to ImplementationClass ?

What should I do to make GetAll return all non-duplicate object?

P.S. I use ninject 2.2

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  1. Editorial Team
    Editorial Team
    2026-05-23T16:27:08+00:00Added an answer on May 23, 2026 at 4:27 pm

    Your binding does not make any sense. You are binding an open generic type to a closed one. It seems that there is a gap in Ninject’s plausibility check for bindings.

    Change the binding to

    kernel.Bind(typeof(GenericAbstractClass<int>)).To(typeof(ImplementationClass));
    kernel.GetAll(typeof(GenericAbstractClass<int>));
    
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