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Home/ Questions/Q 8071391
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Editorial Team
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Editorial Team
Asked: June 5, 20262026-06-05T13:41:05+00:00 2026-06-05T13:41:05+00:00

I have this code: std::string name = kingfisher; char node_name[name.size()+1]; strcpy(node_name,name.c_str()); node_name[name.size()] = ‘\0’;

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I have this code:

std::string name = "kingfisher";
char node_name[name.size()+1];
strcpy(node_name,name.c_str());
node_name[name.size()] = '\0';

It worked well in DevC++, but in Visual C++, i got a problem named “name.size() must be constant value”! How to solve the problem? I know that i have to use a const value in declaration of node_name, but sometimes (like the case above) i cant! thanks!

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  1. Editorial Team
    Editorial Team
    2026-06-05T13:41:06+00:00Added an answer on June 5, 2026 at 1:41 pm
    char node_name[name.size()+1];
    

    As the value of name.size() is not known at compile time, in the above declaration,node_name is variable length array (VLA) which is not allowed in ISO C++.

    In DevC++, it compiles and works, because it provides VLA feature as extension, which is enabled in your compilation configuration.

    Use std::string, or char * along with new[]/delete[], whatever suits your need.

    In your particular case, i.e if you know the string-literal already, then you could write this:

    char node_name[] = "kingfisher"; //this works great!
    

    However, if the string value isn’t known and you want to copy it from somewhere, then do this:

    char *node_name = new char[name.size()+1];
    std::strncpy(node_name, name.c_str(), name.size()+1); //use strncpy
    
    //work with node_name
    
    //must deallocate the memory
     delete []node_name; //not `delete node_name;`
    

    Use std::strncpy instead of std::strcpy, as the former takes the buffer-size also as third argument, as shown above, and the latter doesn’t (which is unsafe usually; not in this case though).

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