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Home/ Questions/Q 916299
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Editorial Team
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Editorial Team
Asked: May 15, 20262026-05-15T18:01:53+00:00 2026-05-15T18:01:53+00:00

I have this code: void getStringWithTag(char* pFile, long sizeSound, char* tag, char* ret, float*

  • 0

I have this code:

void getStringWithTag(char* pFile, long sizeSound, char* tag, char* ret, float* currentPos){
char* tagCopy;
tagCopy = (char*)malloc(256 * sizeof(char));
int totalLen = 0;
int tempLen = 0;
memset(tagCopy, 0, 256);
memset(ret, 0, 128);
pFile += ((int)*currentPos);
while (totalLen+(*currentPos) < sizeSound) {
    if (*pFile == '<') {
        pFile += 5;
        totalLen += 5;
        while(*pFile != '>'){
            *tagCopy = *pFile;
            tagCopy++;
            pFile++;
            totalLen++;
            tempLen++;
        }
        tagCopy -= tempLen;
        tempLen = 0;
        if (strcmp(tagCopy, tag) == 0) {
            pFile++;
            totalLen++;
            while (*pFile != '<') {
                *ret = *pFile;
                ret++;
                pFile++;
                totalLen++;
                tempLen++;
            }
            ret -= tempLen;
            *currentPos += totalLen;
            tagCopy = NULL;
            free(tagCopy);
            return;
        }else{
            memset(tagCopy, 0, 256);
        }
    }
    pFile++;
    totalLen++;
}
tagCopy = NULL;
free(tagCopy);
*currentPos = sizeSound;
ret = NULL;
}

That apparently gives me a memory leak with “tagCopy”.
Can anyone tell me why? I thought I had this down pretty good but this is the only place where I get a memory leak.

Thank you.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-15T18:01:53+00:00Added an answer on May 15, 2026 at 6:01 pm

    You modify tagCopy a few times in that routine, and then you try to free it later. Probably dangerous. You’re also setting tagCopy to NULL before calling free(), so every time you try to free NULL rather than the actual memory you allocated.

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